TN 10TH MATHS EM CH-2 EXAMPLE 2.3
Example 2.3
Show that the square of an odd
integer is of the form 4q+1, for some integer q.
Solution:
Let x be any odd integer.
An even integer x=2k let
Odd integer x=2k+1
GIVEN THAT
The square of an
odd integer x² = (2k+1)²
= (2k)²+2(2k)(1)+ 1²
= 4k²+4k+1
= 4 k(k +1)+1
x² =4q+1 (where q= k(k +1) is
some integer)
*****
HERE CLICK TO DOWNLOAD THE PDF FILE
Comments
Post a Comment